y(x)*y"(x) - [y'(x)]^2 + 1 = 0? - Parajsa Shqiptare Forum

		Parajsa Shqiptare Forum \| Albanian Paradise \| Science & Mathematics
*y(x)y"(x) - [y'(x)]^2 + 1 = 0?**

y(x)*y"(x) - [y'(x)]^2 + 1 = 0?

LinkBack

21-07-2007, 10:57

I/e Sapoardhur

Reg: 21-07-07

Postime: 1

y(x)*y"(x) - [y'(x)]^2 + 1 = 0?

Can anyone find the general solution of this differential equation?

y(x)*y"(x) - [y'(x)]^2 + 1 = 0

__________________
Yahoo! Answers 4ever

Bookmarks

Alternativa Teme
Tregoni Versionin e Pritueshem Dergojeni kete faqe me Email
Vleresojeni kete Teme
Vleresojeni kete Teme:

Rregullore Postimi
You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is aktivizuar Buzeqeshjet jane te aktivizuar Kodi [IMG] eshte i aktivizuar Kodi HTML eshte i dizaktivizuar Trackbacks are aktivizuar Pingbacks are aktivizuar Refbacks are aktivizuar

Kapercim Forumesh

Tema te ngjashme
Tema	Filluesi i temes	Forumi	Pergjigje	Postimi i Fundit
what does the quoted mean "x (something) is lamer than FDR's legs"?	Tsing S	Entertainment & Music	1	05-07-2007 01:35

Te gjitha oret jane ne GMT +1. Ora tani eshte 05:42.