Why is work required to stretch a spring with a linear restoring force?

benzene boy · #1 29-06-2007, 21:35

Explain why the work required to stretch a spring or other elastic object with a linear restoring force, of form F = - kx, from its equilibrium position to displacement x is `dW = .5 k x^2, and why we hence say that this is the elastic potential energy of the object in this position.

titus_meanmac · #2 29-06-2007, 21:55

Work done = change in potential energy (assuming equilibrium conditions)Now, work done (dW) by a force F = dW = F . dx = -Kx.dx = 0.5 K x^2Now this is the work done ON the system and thus it goes into increasing its potential energy (by dW) . This is the energy stored in the spring as potential energy.

Alternativa Teme
Tregoni Versionin e Pritueshem Dergojeni kete faqe me Email
Vleresojeni kete Teme
Vleresojeni kete Teme:

Tema te ngjashme
Tema	Filluesi i temes	Forumi	Pergjigje	Postimi i Fundit
Serbian projects on explusions of Albanians in nineteenth century	Administratori	Illyrians - The Albanians ancestors	0	05-08-2007 16:49
The Pelasgian case	Administratori	Illyrians - The Albanians ancestors	0	05-08-2007 12:06
am i in the right?, phone politics in work.?	absolved lemon	Society & Culture	1	03-08-2007 12:57
Show that the force F defined by F=3x2yi+(x3+1)j+9z2k represent a conservative field	Gayan S	Science & Mathematics	0	30-07-2007 21:27
Latin dictionary!	Administratori	Life & Philosophy	0	27-02-2005 04:20