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#1
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| from this bag.? If the child chooses the marbles at random, what is the chance that the child gets exactly three red marbles?
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#2
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| How many marbles are there in the bag?Your question impossible to be answered due to the lack of information.
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#3
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| Assuming replacement is allowed:P(3) = 6(.3)(.3)(.3)(.7) = 0.2646 or 26.46%If replacement is allowed the total number of marbles is irrelevant since we are given P = 0.7 as a constant. If replacement is not allowed then P will vary as marbles are picked and the number of total marbles is relevant to determining the answer.
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#4
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| Here is my vote:There are four ways of getting three red and one black BRRRRBRRRRBRRRRBFor each way, the probability of that way is p x p x p x p , where p =0.7 is the probability of black and p is the probability of red. Hence the overall probability is4 x 0.7 x 0.3 x 0.3 x 0.3 = 0.0756which is equivalent to a 7.56% chance.
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