Help. I've asked a couple friends and we all come up with the same

babyblu_207 · #1 23-07-2007, 08:34

answer, but it is not right.? How many ways are there to select five unordered elements from a set with three elements when repetition is allowed?

pyerzuka · #2 23-07-2007, 08:35

I hope this is what you mean but here it goes.

Elements:
1A 2B 3C
Order:
A>B>C>B>A

gp4rts · #3 23-07-2007, 08:35

Consider that each of the five unordered elements can have any one of three values. If there were only two unordered elements, the number of ways would be 3 times 3, or 3^2. Similarly, for five unordered elements with repetition, the number of ways is 3^5.

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