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| At what point(s) does y=(x^2 + 5)(x-5) have slope 2? I know how to find the tangent line at a point of a function so i tried working backwards to do this problem but the more i think about it, the more im getting confused. I took the derivative of y and got 3x^2 - 10x + 5 now do i set that to 2?
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