Find the slope of any line perpendicular to the line through pts. (0, 5) and (-3,

associates07 · #1 27-06-2007, 15:35

-4)? Find the slope of any line perpendicular to the line through pts. (0, 5) and (-3, -4)? Thank you

DeSeRT EaGLe · #2 27-06-2007, 15:55

hiwhen 2 line are perpendicular : m1 * m2 = -1m1 = (-4-5) / (-3-0) = 3therefore the slope of the line = -1/3as 3 * -1/3 = -1

Doctor Q · #3 27-06-2007, 16:46

Work out the gradient of this line.....-3 - 0 = -3-4 - 5 = 9Gradient = 9 / -3 = -3So any line perpendicular means that -3 * x = -1 (where x is the gradient of the other line)In this case x = 1/3, as -3 * 1/3 = -1

minorchord2000 · #4 27-06-2007, 17:35

slope, m, = delta y/delta x = 5-(-4)/(0-(-3)) = 9/3 = 3

yljacktt · #5 27-06-2007, 17:46

The slope through those point is (-4-5)/(-3-0) = -9/-3 = 3.So, the slope of any line perpendicluar is the negative inverse, or -1/3.

tripe · #6 27-06-2007, 17:56

gradient = m = (5 - -4)/(0 - -3)= 9gradient of perpendicular line = -1/m = -1/9

ayudame · #7 27-06-2007, 18:35

y2-y1-------x2-x15-(-4)-----0-(-3)9--3m=3perpendicular m= -1/3

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