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| So the question goes like this: A TV camera at ground level is filming the liftoff of a space shuttle that is rising vertically according to the position eqn: s(t)=50t^2, where s is measured in feet and t is measured in seconds. The camera is 2000 feet from the launch pad. Find the velocity of the space shuttle when it is 5000ft high. [[I did this already, and I got 1000 ft/s. I know that it is right.]] Find the rate of change in the angle of elevation of the camera when the space shuttle is 5000 ft. high. [[I can't figure this one out for the life of me. I think it has something to do with inverse tangent, and with the previous anwser (1000 ft/sec).]] So for the second part... is my answer of 2/29 right?
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