wouldnt the answer be 10??

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it is equal to 10.240

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actually it would be 10.22.0 is your limitation on significant figures.math prof below has a good explanationACTUALLY - 10 has only ONE significant figure.. zeros on the end do NOT count as significant (only after the decimal do they count when on the end)

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If you are using one significant figure, then the answer would be 10.However, 5.12 has three sig fig and 2.0 has one.One could conclude that the product should have three sig fig so the answer would be 10.2.

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I think some people answered your question already, but just wanted to chime in about significant figures...5.12 has 3 sig figs.2.0 has 2 (not 1) sig figs.Answer should be "10." (with the decimal point but no zero behind the decimal point)Remember, the number of digits behind a decimal point always contribute to sig figs. The number of sig figs in an answer is determined by the number with the least number of sig figs in the original equation. The zero(s) in front of the decimal point don't count if the number is an integer, there is no decimal point, and the zero(s) are at the end of the number.

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5.12 has 3 sig figs. 2.0 has 2 sig figs. The answer is 10.24 and since 2.0 has 2 sig figs, the answer is 10. I checked it on my TI-84 that has a sig fig calculator.

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When a decimal point is present, all zeros between that decimal point and a digit are significant digits.When a decimal point is not present, any zero not trapped between two nonzero digits are insignificant:103 has 3 sf's1030 has 3 sf's1030. has 4 sf's1030.00 has FIVE sf's00010.0 has 3 sf'sSince your limiting value is 2.0, which hereby has TWO significant digits, the answer 10.24 must be rounded to have TWO significant digits. 10.24 raw has four significant digits10.2 would be THREE significant digits10. would be two significant digits.To clear things up.. The answer is not just "10", but "10.".It has to have a decimal point for that zero in the units' place to count.

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