Tema: what is the equation of the linear function that passes through (6,-4) and is
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Te vjeter 27-06-2007, 15:55
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Reg: 27-06-07
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4x - 2y = 4-2y = -4x + 4y = 2x - 2Slope of given line is 2Slope of a line parallel is also 2.So, using point-slope form:y - y1 = m(x - x1)y - (-4) = 2(x - 6)y + 4 = 2x - 12y = 2x - 16Or, in standard form: 2x - y = 16
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